Please solve the following equation:
1 answer:
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Answer:
The mixture contains 80% water and 20% alcohol.
Step-by-step explanation:
Given:
Total Amount of mixture = 60 oz
Amount of alcohol in the mixture = 12 oz
We need to find the percentage of water and percentage of alcohol in the mixture.
Solution:
First we will find the amount of water in mixture.
Now we know that;
Total Amount of mixture is equal to sum of Amount of alcohol in the mixture and amount of water in mixture.
so we can say that;
amount of water in mixture = Total Amount of mixture - Amount of alcohol in the mixture
amount of water in mixture =
Now we will find the Percentage amount of water.
Percentage amount of water can be calculated by dividing amount of water in mixture by Total Amount of mixture and then multiplying by 100.
framing in equation form we get;
Percentage amount of water =
Percentage amount of alcohol =
Hence The mixture contains 80% water and 20% alcohol.
164 inches x =
ft
147 inches x =
ft
2ft =
Perimeter = 2L + 2w - 1doorway
= 2 + 2(
-
= +
-
= +
= +
= +
=
= 49ft
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b) 49ft ÷ 8ft = 6.2
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