3 years ago

Thank you guys fir the help

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

4 0

The correct answer to that would be b

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Solve the inequality 2x + 5 2 27

devlian [24]

Answer:

$2x + 5 \geqslant 27 \\ = 2x \geqslant 27 - 5 \\ = 2x \geqslant 22 \\ = x \geqslant 22 \div 2 \\ x \geqslant 11 \\ x[11 \: \infty ) \\ thank \: you$

5 0

2 years ago

Read 2 more answers

PLEASE HELP THANK YOU!!!!

insens350 [35]

//// For G(x) = -1/4x - 1////
G(-5) = -1/4(-5) - 1 = 0.25;
G(-2) = -1/4(-2) - 1 = -0.25;
G(-1) = -1/4(-1) - 1 = -0.75;
///////////////////////////////////

////For G(x) = (x-1)^2 - 3////
G(-1) = ((-1) -1)^2 - 3 = 1;
G(-2) = ((-2) - 1)^2 - 3 = 6;
G(-5) = ((-5) - 1)^2 - 3 = 33;
//////////////////////////////////////////

////For G(x) = 1/4x + 2////////
G(-5) = 1/4(-5) + 2 = 0.75;
G(-2) = 1/4(-2) + 2 = 1.5;
G(-1) = 1/4(-1) + 2 = 1.75;

3 0

3 years ago

Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for

e-lub [12.9K]

Answer:

a) Hence the endpoints of a t-distribution with 5% beyond them in each tail if the sample has size n=12 is ± 1.796.

b) Hence the endpoints of a t-distribution with 1% beyond them in each tail if the sample has size n=20 is ± 2.539.

Step-by-step explanation:

Here the answer is given as follows,