Answer:
Below.
Step-by-step explanation:
Working together the rate is 80 + 120 = 200 gallons per minute.
(a) Time to fill tank = 6000 / 200 = 30 minutes.
(b) Let length of time the small pipe was used be x minutes , the the large pipe was used for is 60-x minutes.
Volume delivered by small pipe = y gallons, and by large pipe = 6000-y gallons.
Rate for small pipe = 80 = y/x.
Rate for large pipe = 120 = (6000-y) / 60-x.
y/x = 80
(6000-y) / 60-x = 120
From first equation y = 80x so:
6000 - 80 x = 7200 - 120x
40x = 1200
x = 30
So time for small pipe = 30 and time for large on = 30 minutes also.
C. In a similar way to part B:
y/x = 120
(6000-y) / 34 - x = 200
(6000-120x) / 34 - x = 200
6000 - 120x = 6800 - 200x
80x = 800 so the large pipe on its own took 10 minutes and the small pipe was used for 34 - 10 = 24 minutes.
2*10^-3 + 3*10^-3
(2+3)*10^-3
5*10^-3
since the sum of coefficients of the 10^-3 are less than 10, we still have the same number of zeros
0.005
Answer:
ADB and DBC
Step-by-step explanation:
Angles ADB and DBC are both marked with three curved lines which shows that their angles are congruent to each other.
Hope this helps! :)
Answer:
sin
(
x/
2
) = -
√
3
/2
Take the inverse sine of both sides of the equation to extract x
from inside the sine.
x/
2
=
arcsin
(
−
√
3/
2
)
The exact value of arcsin
(
−
√
3
/2
) is −
π
/3
.
/x
2
=
−
π
/3
Multiply both sides of the equation by 2
.
2
⋅
x
/2
=
2
⋅
(
−
π
/3
)
Simplify both sides of the equation.
x
=
−
2
π
/3
The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from 2
π
, to find a reference angle. Next, add this reference angle to π to find the solution in the third quadrant.
x
/2
=
2
π
+
π/
3
+
π
Simplify the expression to find the second solution.
x
=
2
π
/3
4
π
Add 4
π to every negative angle to get positive angles.
x
=
10
π
/3
The period of the sin
(
x
/2
) function is 4
π so values will repeat every 4
π radians in both directions.
x
=2
π
/3
+
4
π
n
,
10
π/
3
+
4
π
n
, for any integer n
Exclude the solutions that do not make sin
(
x
/2
)
=
−
√
3/
2 true.
x
=
10
π
/3
+
4
π
n
, for any integer n
Which one is the positive slope A.) (2,-3,) and (1,-2), B.) (0,0) and (3,-3), C.) (-1,-1) and (5,4) , D.) (-3,0), (9,0)
bagirrra123 [75]
Answer:
C.
Step-by-step explanation:
Use slope = (y2-y1)/(x2-x1).
slope = (4 - -1)/(5 - -1)
slope = 5/6, positive
Hope this helps!
