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Arisa [49]
3 years ago
6

What is the next term in the sequence? 44, 22, 11, 5.5...

Mathematics
1 answer:
sattari [20]3 years ago
8 0
This is a geometric sequence and the common ratio is 0.5.

So, the next term will be 2.75.
You might be interested in
9 [1+345-(6-8 +48 x 23 -77​
melisa1 [442]

Answer:

1933

Step-by-step explanation:

9 x (1 + 345) - 6 - 8 + 48 x 23 - 77

Use BODMAS method to solve these type of equation

B - Brackets

O - Power

D - Division

M - Multiplication

A - Addition

S - Subtraction

_________________________________________________________

Brackets - 1 + 345 = 346

Multiplication

9 x 346 = 3114

48 x 23 =  1104

Lets rewrite the equation now

3114 - 6 + 1104 - 77

Addition

6 + 1104 = 1110

Subtraction

3114 - 1104 = 2010

2010 - 77 = 1933

Answer = 1933

__________________________________________________________

Hope you understand

:-)

6 0
3 years ago
Brittany bought three movies from the library which movie is almost 3 hours long about how many hours of movies does Britney hav
Anton [14]
Britney has to watch 90 hours of movies
5 0
2 years ago
Read 2 more answers
Any one have ideas of how to do this... haha I am so lost
Anastasy [175]
How the heck r we supposed to solve that if it says “evaluate 5!”
4 0
2 years ago
Analyze the diagram below and answer the question that follows.
Vlada [557]
This would be a scalene triangle, because all of the sides are different lengths.

The correct answer is C.

6 0
3 years ago
Read 2 more answers
Hi, can you help to find (all the roots/zeros), please!!!
OLga [1]

Solution

Given the quadratic equation

x^2-2x-38=0

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\  \\ \Rightarrow x^2-2x=38 \end{gathered}

Step 2: add the square of half of the coefficient of x to both sides

That is;

\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\  \\ \Rightarrow x^2-2x+1=38+1 \\  \\ \Rightarrow x^2-2x+1=39 \\  \\ \Rightarrow(x-1)^2=39 \end{gathered}

Step 3: Simplify the above expression;

\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\  \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}

4 0
10 months ago
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