Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).
Second one
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Hope it helps
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Answer:
(-1,-1)
Step-by-step explanation:
If you multiply the x and y points of A, (-3,-3), by 1/3 then you find: (-1,-1).