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Ray Of Light [21]

3 years ago

8

An above ground swimming pool is leaking. After 1/2 hour the pool has leaked 7/8 of a gallon of water. How many gallons of water

per hour is the swimming pool leaking?

1 answer:

Lilit [14]3 years ago

6 0

1 $\frac{3}{4}$ , or 1.75<u />

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Help!!! I dont know how to do this

Luda [366]

Your answer is -3...if i did this right.

7 0

4 years ago

3 1/5 ÷(z− 1/2 )=2 2/3 ÷(z+ 1/3 )

love history [14]

Answer:

10

Step-by-step explanation:

if u take 5x2 u get your answer

5 0

3 years ago

Read 2 more answers

Does anyone understand this? show work please. thank you.

snow_tiger [21]

Answer:

You need to satisfy the equation.

I will solve one.

Step-by-step explanation:

x -2 < -5

now add + 2 to both sides to keep its value.

now we end up with x <-3, which means that the value of x should be less than -3 in order to satisfy the equation.

So -5 is an answer, -4 is an answer, but not -3 because it should be less than -3 not equal.

As for number 9 the dash underneath the less than symbol means that it can equal to.

Hope this helps.

3 0

3 years ago

Read 2 more answers

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago

Finding the missing angles ?

bazaltina [42]

Answer:

1. 46

2. 46

3. 134

4. 134

5. 46

6. 46

7. 134

This is going from top right, left to right.

8 0

2 years ago