Answer:
See attached for the cyclic quadrilateral
To prove: <BAD + <BCD =180°
Construction: Join B and D to the centre O of circle ABCD
Proof
With the lettering of the attached drawing,
<BOD = 2y (angle at centre is 2 X angle at circumference)
Reflex <BOD = 2x (angle at centre is 2 X angle at circumference)
∴ 2x + 2y = 360° (angle at point)
∴ x + y = 180°
∴ <BAD + <BCD = 180°
Step-by-step explanation:
The vertices of a cyclic quadrilateral lie on the circumference of the circle and the opposite angles of a cyclic quadrilateral lie in opposite segment of a circle.
The question is to prove that the opposite angles of a cyclic quadrilateral are supplementary that is 180°. Another way of stating this theory is 'Angles in opposite segments are supplementary'.
Note that the sum of supplementary angles is 180°.
Answer:
x:0.3=5:6-->x/0.3=5/6-->6×x=0.3×5-->6x=1.5-->x=1.5/6-->x=0.25Answer..
I believe the answer is 3*g but don't use x because it could be mistaken as a variable.
Step-by-step explanation:
Given line is 6x+3y=15
Slope of the given line (m)=-x/y
=-6/3
=-2
let slope of the line perpendicular to the given line be m'.
Condition of perpendicularity,
m×m'=-1
-2×m'=-1
m'=-1/-2
m'=1/2
