Using the form y=a(x-h)²+k
We can look at the vertex (-3,-2) which gives us the values of h,k
h=3, k=-2
Thus y=a(x+3)²-2
Then we can solve for a using any point on the line
- I'll use (-4,-1)
Insert the values of x,y into y=a(x+3)²-2
--> x=-4, y=-1
y=a(x+3)²-2
-1=a(-4+3)²-2
-1=a(-1)²-2
a-2=-1
a=-1+2
a=1
Insert the value of a
y=1(x+3)²-2
= (x+3)²-2
Thus y=(x+3)²-2 is the final equation in standard form
Answer:
Step-by-step explanation:
In a parallelogram, this one in particular:
KR = RM
JR = RL
We are looking in the end for the length of JR, but that means that we need to solve for x somehow to plug in the expression for JL, and then split that in half. Here's how we're going to go about it. I know that
KM = KR + RM, but since KR and RM are the same length, the equation becomes
KM = 2KR. Filling that in with the expressions I'm given for KM and KR:
3x - 5 = 2(x + 7) and
3x - 5 = 2x + 14 and
x = 19. Now I can find the length of JL:
JL = 4x - 10 so
JL = 4(19) - 10 and
JL = 66
Knowing that JR = RL and JL is 66 units long, JR = RL = 33 units each.
Answer:
E
Step-by-step explanation:
3/5=a/m 3m/5=a
m-3m/5=80
2m/5=80
m=200
Answer:
The minimum cost per unit is obtained for an order of 8 units.
Step-by-step explanation:
Since the total cost is modeled by;
C(x)=5x²+320
Then;
1 unit costs; C(x)=5(1)²+320 = 325
cost per unit 325/1 = 325
8 units costs; C(x)=5(8)²+320 = 640
cost per unit = 640/8 = 80
80 units costs; C(x)=5(80)²+320 = 32320
Cost per unit = 32320/80 = 404
The minimum cost per unit is obtained for an order of 8 units.
