What is 0.18 repeating as a fraction

Amanda uses her Credit card to purchase $75 of materials Amanda pays her credit card off each month

stealth61 [152]

The remaining balance that Amanda will pay when the credit card is used to pay $75 from the total amount is $125.

<h3>How to compute the amount?</h3>

Your information is incomplete. Therefore, an overview will be given. Let's assume that the total purchase made by Amanda is $200.

In this case, she uses her credit card to make payment for $75. Therefore to know the remaining balance, you'll subtract $75 from the total purchase. This will be:

= $200 - $75

= $125

Learn more about credit card on:

brainly.com/question/6872962

5 0

2 years ago

Write the function in standard form f(x) = -5 (x-7)^2 +11

Lapatulllka [165]

3x+1=1 because it is a hard problem to solve just ask your teacher

6 0

3 years ago

Read 2 more answers

⚠️ANSWER NEEDED FASTT⚠️ *BRAINLIEST TO RIGHT ANSWER*

s344n2d4d5 [400]

Answer:

I think like its like the like 4th right 1 i think right

Step-by-step explanation:

4 0

3 years ago

The _______ are all the counting numbers.

Bingel [31]

It cannot be be Integers because Integers include negative numbers (which are not counting numbers)

It cannot be real numbers because like integers, it includes negative numbers but also includes decimals which are not counting numbers

It cannot be absolute values because absolute values is the range of how far away a number is from 0 which obviously isn't counting

That leaves natural numbers which are counted in sequence which fits the definition needed

Answer: D. Natural Numbers

5 0

3 years ago

Read 2 more answers

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago