1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fofino [41]
3 years ago
13

Both gases and ___________ exert a buoyant force.

Chemistry
2 answers:
Softa [21]3 years ago
7 0

Answer:

Liquids APEX Verified

Explanation:

lbvjy [14]3 years ago
5 0
<span>Both gases and ___fluids/liquids________ exert a buoyant force.</span>
You might be interested in
A 0.2 m solution of a weak acid ha dissociates such that 99.4% of the weak acid remains intact (i.e., remains as ha). what is th
Kobotan [32]
HA -----> H(+) + A(-)
0,2-x.........x..........x

100% - 99,4% = 0,6% = 0,006

x = 0,6%×0,2 = 0,006 × 0,2 = 0,0012

HA --------------> H(+) + A(-)
0,2-x.....................x..........x
0,2-0,0012.....0,0012..0,0012
0,1988.............0,0012..0,0012

K = [H+][A-]/[HA]
K = (0,0012)^2/0,1988
K = 0,0000072434

pKa = -logK= -log0,0000072434 = 5,14

:)
3 0
3 years ago
In an aqueous chloride solution cobalt(II) exists in equilibrium with the complex ion CoCl42-. Co2 (aq) is pink and CoCl42-(aq)
kolezko [41]

Answer:

1. This reaction is <u>(A) Exothermic .</u>

2. When the temperature is decreased the equilibrium constant, K: <u>(A) Increases</u>

3.When the temperature is decreased the equilibrium concentration of Co2:<u> (A) Increases</u>

Explanation:

CoCl4^2-(aq)  Co_2+(aq) + 4Cl^-(aq)

1. The pink color predominates at low temperatures, indicating that the commodity is preferred.

This is a reaction that is <u>exothermic.</u>

2. As the decrease in the temperature , the equilibrium constant , K ;

      equilibrium constant = \frac{product}{reactant} =\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}

As the temperature drops, the concentration ofCl^- and CO^2^+ rises, and K rises as well , thus it <u>increases </u>.

3. The equilibrium concentration of CO^2^+ decreases as the temperature decreases:

When the temperature is lowered, the equilibrium shifts to the right , that is it <u>increases.</u>

4 0
3 years ago
Which of the following statements is true about taste bud preferences?
Dafna1 [17]
It seems that you have missed the necessary options for us to choose from, but anyway, here is the answer. The statement that is considered true about taste bud preferences would be this: The taste buds are located within the papillae of the tongue. Hope this answers your question.
6 0
3 years ago
H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles
abruzzese [7]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

H_2(g)+F_2(g)\rightarrow 2HF(g)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]

We are given:

\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = \frac{-14.1}{1}\times 2.20=-31.02J/K

Hence, the value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0
3 years ago
What do the edifices from the hot water vent look like and what they are made of?​
netineya [11]

Answer:

Water heaters must have vent to the outside of the heater to remove exhaust air from the water heater, the vent go directly through it walls. It is likened to the vent in natural gas water heater which have a vent to the outside that remove by products of combustion and can also bring in air combustion.

The edifice from the hot water vent are made of metals or plastic materials depending on the venting systems.

3 0
4 years ago
Other questions:
  • A chemist prepares a solution of iron(II) bromide FeBr2 by measuring out 0.55kg of iron(II) bromide into a 500.mL volumetric fla
    14·1 answer
  • Amanda found two snakes slithering in her garden. The first snake way only a baby,and was just 3/4 of an inch long. The second s
    12·1 answer
  • What is the relationship between an observation and an inference?
    11·1 answer
  • What is the volume of the item described?
    7·1 answer
  • What is a direct current?
    8·1 answer
  • assuming gasoline can be represented as C8H18, how much oxygen is needed to completely burn this fuel. answer in grams of oxygen
    13·1 answer
  • Which state of matter expands when heated and is easy to compress?
    11·2 answers
  • PLEASE HELP ME ASAP!!!
    6·2 answers
  • Can u pls help me with this question ​
    8·1 answer
  • This homework assignemnt is confusing can someone please help.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!