A chemist prepares a solution of iron(II) bromide FeBr2 by measuring out 0.55kg of iron(II) bromide into a 500.mL volumetric fla
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Answer: 19.25 gallons
Explanation: 1 ml = 0.0011 quart
Given: 4 quarts = 1 gallon
Thus if 1 ml is equal to 0.0011 quart
70000 ml is equal to =
Now if 4 quarts is equal to 1 gallon.
77 quarts is is equal to=
Answer : The mass of produced will be, 5.3 grams.
Explanation : Given,
Mass of = 1.74 g
Mass of = 11 g
Molar mass of = 58 g/mole
Molar mass of = 32 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 13 mole of
So, 0.03 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of .
As, 2 moles of react to give 8 moles of
So, 0.03 moles of react to give
moles of
Now we have to calculate the mass of .
Therefore, the mass of produced will be, 5.3 grams.