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umka2103 [35]
3 years ago
14

A chemist prepares a solution of iron(II) bromide FeBr2 by measuring out 0.55kg of iron(II) bromide into a 500.mL volumetric fla

sk and filling the flask to the mark with water.
Calculate the concentration in /molL of the chemist's iron(II) bromide solution.
Round your answer to 2 significant digits
Chemistry
1 answer:
Sidana [21]3 years ago
7 0
Molar mass of ferrous bromide: 215.65<span>
m(FeBr2): 550/215.65 = 2.55moles
this is dissolved in 500mL of water so in 1L of solution there will be 2.55x2 = 5.1mol/L</span>
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Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make ac
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The energy of the carbide released is 7262.5MJ.

<h3>What is the energy?</h3>

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g). The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

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7 0
1 year ago
What is the mass of water necessary to generate 11.2 L of hydrogen gas if calcium metal reacts with water at standard temperatur
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Answer:

The mass of water is 18 g

Explanation:

The reaction of calcium with water can be represented in the equation below:

Ca + 2H₂O --------->Ca(OH)₂ +H₂

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From the displacement reaction above, calculate the mass of water that will produce 22.4L of hydrogen gas at STP.

Mass of 2H₂O = 2(2x1 + 16) = 2X18 = 36 g/mol

Using proportional analysis;

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what mass of 2H₂O will produce 11.2L of  H₂ ?

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22.4 L ----------------------------------> 36g

11.2 L -----------------------------------> ?

Cross and multiply, to obtain the expression below

= (11.2 X 36)/22.4

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The length of a vector arrow represents its magnitude and the point represents its direction
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3 years ago
Read 2 more answers
How many grams of hydrochloric acid are produced when 15.0 grams NaCl react with excess H2SO4 in the reaction
e-lub [12.9K]

Answer:

11.65 g

Explanation:

Amount of NaCl  = 15.0 grams

amount of H₂SO₄ = Excess

mass of hydrochloric acid (HCl) = ?

Solution:

To solve this problem first we will look for the reaction that NaCl react with  H₂SO₄

Reaction:

         2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄

As the  H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.

Now if we look at the reaction

         2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄

           1 mol                              2 mol  

Now convert moles to mass

Then

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

So,

            2NaCl           +      H₂SO₄     -------->       2HCl        +     Na₂SO₄

      2 mol (58.5 g/mol)                                    2 mol (36.5 g/mol)

              94 g                                                           73 g

So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl

For this apply unity formula

           94 g of NaCl  ≅ 73 g of HCl

           15.0 g of NaCl  ≅ X g of HCl

By Doing cross multiplication

           X g of HCl = 73 g x 15.0 g / 94 g

           X g of HCl = 11.65 g

11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl

7 0
3 years ago
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