Answer: A
The lines have the same slope but different y-intercepts.
39.15 ^-^
YOUR WELCOME
sorry for caps lock lol
Answer:
6,690 boxes per hour
Step-by-step explanation:
Given:
Number of boxes fill = 6,021
Time is taken = 0.9 hour
Find:
Number of boxes fill per hour
Computation:
Number of boxes fill per hour = Number of boxes fill (1 hour / Time taken)
Number of boxes fill per hour = 6,021 (1 hour / 0.9 hour)
Number of boxes fill per hour = 6,690
Due to length restrictions, we kindly invite to see the explanation below to know the answer with respect to each component of the question concerning linear equations.
<h3>How to determine a linear equation describing the daily distance of a runner</h3>
In this question we need to derive an expression of the <em>daily</em> distance as a function of time. Now we proceed to complete the components:
- <em>Linear</em> equations have an <em>independent</em> variable (t - time) and a dependent variable (x - daily distance).
- We notice that the daily distance increases linearly in time, then then we have the following pattern:
t 1 2 3 4 5 6
x 2 2.5 3 3.5 4 4.5 - The equation that represents the n-th term of the sequence is x(n) = 2 + 0.5 · (n - 1).
- The week when Susie will run 10 miles per day is:
10 = 2 + 0.5 · (n - 1)
8 = 0.5 · (n - 1)
n - 1 = 16
n = 17
Susie will run 10 miles per day in the 17th week. - It is not reasonable to think that pattern will continue indefinitely as it is witnessed in the difficulties experimented by <em>fastest</em> runners in the world to increase their <em>peak</em> speeds.
- A marathon has a distance of 26 miles, then we must solve the following equation:
26 = 2 + 0.5 · (n - 1)
24 = 0.5 · (n - 1)
48 = n - 1
n = 49
Susie should start her training 49 weeks before the marathon.
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The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours. Option A
<h3>Equation</h3>
c(h) = 250 + 200h
s(h) = 300 + 180h
Where,
- number of credit hours taken = h
To have equal tuition in both schools,
equate both function
250 + 200h = 300 + 180h
200h - 180h = 300 - 250
20h = 50
h = 50/20
h = 2.5 hours.
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours.
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