Given: Hockey teams receive $2$ points when they win and $1$ point when they tie. One season, a team won a championship with $66$ points. They won $12$ more games than they tied.

To Find: How many wins and how many ties did the team have.

Solution:

let the number of wins hockey team have $=\text{x}$

let the number of ties hockey team have $=\text{y}$

Now,

Hockey teams receive $2$ points when they win and $1$ point when they tie.

$2\text{x}+\text{y}=66$

They won $12$ more games than they tied

$\text{x}-\text{y}=12$

Solving both equations we get

$\text{x}=26$

$\text{y}=14$

Hence, the hockey team have $26$ wins and $14$ ties.

3 0

3 years ago

What's the answer to this ?? Need help

Veseljchak [2.6K]

It goes by 3s so I think its 1.2

5 0

3 years ago

Read 2 more answers

Write an equation in slope intercept form for the line through the two points

Musya8 [376]

$m= \frac{y2-y1}{x2-x1} \\ \\ m= \frac{-2-2}{2-(-2)} \\ \\ m= \frac{-4}{4} \\ \\ m=-1$

$y=mx+b \\ \\ y=-1x+b$

$(2)=(-1)(-2)+b \\ \\ 2=2+b \\ \\ 0=b$

$y=-1x+0 \\ \\ y=-x$

5 0

3 years ago