20^2 = 16^2 +x^2
400= 256+ x^2
x^2 = 400 -256
x = 144^1/2
=12
b. yes
Hey!
The answer would be (4,8)
You separate the inequalities first
-2x + 6>-10
-2x + 6<-2
Then you solve the inequalities
X<8
X>4
Then find the intersection
(4,8)
And there you go! Hope this helps!
You cannot add -10y+9x or 10y+5x because of the rule “combine like terms”...
Isn't that Roman Numerals? But anyways,
L = 50
X = 10
X = 10
IV = 4.
So, 50 + 10 + 10 + 4 = 74.
The answer to your question is 74.
It would be first 0.86 then it would be 8/9 and the le last one would be 0.9
