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4 years ago

14

In a sheet metal operation, three identical notches and four identical bends are required. If the operations can be done in any

order, how many different possible sequences are there to complete the manufacturing?

1 answer:

goldfiish [28.3K]4 years ago

3 0

Answer:

<h2>There are 5040 different possible sequences.</h2>

Step-by-step explanation:

Three identical notches and four identical bends are required in the sheet metal operation.

In total 7 things are required in the metal operation.

We can think it as we need to put the 3 notches and 4 bends in 7 places.

First, lets put the 3 notches in 3 places.

In order to do so, we need to choose 3 places from the 7 places.

We can choose 3 places in $\frac{7!}{3!\times4!} = \frac{5\times6\times7}{6} = 35$ ways.

The 3 notches can be arrange in 3! = 6 ways.

The 4 bends can arrange in 4! = 24 ways.

Thus, in total $35\times24\times6 = 5040$ different possible sequences.

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Will mark Brainlest please answer. find the value of a,b. <br>,p,q from the equal order pairs

NARA [144]

Step-by-step explanation:

<h3>Question-1:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 3p = 2p - 1 \dots \dots i\\2q - p = 1 \dots \dots ii\end{cases}$

cancel 2p from the i equation to get a certain value of p:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - p = 1 \end{cases}$

now substitute the value of p to the second equation:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - ( - 1) = 1 \end{cases}$

simplify parentheses:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q + 1= 1 \end{cases}$

cancel 1 from both sides:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q = 0\end{cases}$

divide both sides by 2:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\q = 0\end{cases}$

<h3>question-2:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\3y= x + y \dots \dots ii\end{cases}$

cancel out y from the second equation:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\ x = 2y \dots \dots ii\end{cases}$

substitute the value of x to the first equation:

$\displaystyle \begin{cases} \displaystyle 2.2y-y= 3 \\ x = 2y \end{cases}$

simplify:

$\displaystyle \begin{cases} \displaystyle 3y= 3 \\ x = 2y \end{cases}$

divide both sides by 3:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2y \end{cases}$

substitute the value of y to the second equation which yields:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2 \end{cases}$

<h3>Question-3:</h3>

by order pair we obtain;

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \dots \dots i\\3q + 2p = 3 \dots \dots ii\end{cases}$

rearrange:

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \\2p + 3q= 3 \end{cases}$

subtract and simplify

$\displaystyle \begin{array}{ccc} \displaystyle 2p + q = 2 \\2p + 3q= 3 \\ \hline - 2q = - 1 \\ q = \dfrac{1}{2} \end{array}$

substitute the value of q to the first equation:

$\displaystyle 2.p+ \frac{1}{2} = 2$

make q the subject of the equation:

$\displaystyle p = \frac{3}{4}$

hence,

$\displaystyle q = \frac{1}{2} \\ p = \frac{3}{4}$

3 0

3 years ago

Read 2 more answers

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Alborosie

Answer:

b. 36

Step-by-step explanation:

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3 years ago

Eloise made a list of some multiples of 8/5. Write 5 fractions that could be in her list

Vlada [557]

Hey there! :D

If you multiply the top and bottom by the same number, you can get fractions that are equivalent.

8/5 (*2)= 16/10

8/5 (*3)= 24/15

8/5 (*4)= 32/20

8/5 (*5)= 40/25

8/5 (*6)= 48/30

There are just a few. You can do many more!

I hope this helps!
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4 years ago

When the women's soccer team won the state championship, the parent boosters welcomed the team back to school with a balloon b

Ray Of Light [21]

Answer:

Each bouquet included 8 latex balloons and 4 foil balloons

Step-by-step explanation:

Hi there!

Let x be the number of latex balloons and y the number of foil balloons. The total cost of the balloons will be the cost of each latex balloon times the amount (x) added to the cost of each foil balloon times the amount of these balloons (y). Then:

Cost of each latex balloon = 0.14

Amount of latex balloon = x

Cost of each foil balloon = 1.96

Amount of foil balloons = y

0.14 x + 1.96 y = 161.28

We also know that each player received 12 balloons. Since there are 18 players, the number of foil and latex balloons will be 18 · 12 = 216 balloons.

Then:

x + y = 216

So we have a system of equations that we can solve because we have two equations and two unknowns. Let´s solve it!

0.14 x + 1.96 y = 161.28

x + y = 216

Let´s solve the second equation for y:

x + y = 216

y = 216 - x

Now, let´s replace y in the first equation and solve it for x:

0.14 x + 1.96 y = 161.28

0.14 x + 1.96 (216 - x) = 161.28

Apply distributive property:

0.14 x + 423.36 - 1.96 x = 161.28

-1.82 x + 423.36 = 161.28

-1.82 x = 161.28 - 423.36

-1.82 x = -262.08

x = -262.08 / -1.82

x = 144

There are 144 latex balloons

Then:

y = 216 -144 = 72

There are 72 foil balloons

If 144 latex balloons are distributed among the 18 players, each player will receive (144/18) 8 balloons.

In the same way, if the 72 foil balloons are distributed among the players, each will receive (72/ 18) 4 balloons.

Then, each bouquet included 8 latex balloons and 4 foil balloons.

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3 years ago

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Answer: ok funny but do you play madden20

Step-by-step explanation:

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4 years ago