Question

What is the value of n? n–2=10n+42

Answer 1

N-2=10n+42
Add 2 to both sides
n=10n+44
Subtract 10n from both sides
-9n=44
Divide both sides by -9
n=(-44/9)

Answer 2

To solve this equation we have to find the value of $n$:

$n-2=10n+42$    

We have to join the terms with $n$ in one side of the equation, and the other terms by the other side:

$n-10n=42+2$    

Then:

$-9n=4$    

-9 is multiplying $n$ and it goes to the other side dividing. Then we have the final result:

$n=-\frac{44}{9}$