Answer:
Part 1)
-------> 
Part 2)
-------> 
Part 3)
-----> 
Part 4)
----> 
Part 5)
-------> 
Step-by-step explanation:
Part 1) we have

Find the inverse
Let
y=f(x)

Exchange the variables x for y and t for x

Isolate the variable y
![x=\frac{2y-1}{y+2}\\ \\ xy+2x=2y-1\\ \\xy-2y=-2x-1\\ \\y[x-2]=-2x-1\\ \\y=\frac{-2x-1}{x-2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2y-1%7D%7By%2B2%7D%5C%5C%20%5C%5C%20xy%2B2x%3D2y-1%5C%5C%20%5C%5Cxy-2y%3D-2x-1%5C%5C%20%5C%5Cy%5Bx-2%5D%3D-2x-1%5C%5C%20%5C%5Cy%3D%5Cfrac%7B-2x-1%7D%7Bx-2%7D)
Let


Part 2) we have

Find the inverse
Let
y=f(x)

Exchange the variables x for y and t for x

Isolate the variable y
![x=\frac{y-1}{2y+1}\\ \\2xy+x=y-1\\ \\2xy-y=-x-1\\ \\y[2x-1]=-x-1\\ \\y=\frac{-x-1}{2x-1}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7By-1%7D%7B2y%2B1%7D%5C%5C%20%5C%5C2xy%2Bx%3Dy-1%5C%5C%20%5C%5C2xy-y%3D-x-1%5C%5C%20%5C%5Cy%5B2x-1%5D%3D-x-1%5C%5C%20%5C%5Cy%3D%5Cfrac%7B-x-1%7D%7B2x-1%7D)
Let


Part 3) we have

Find the inverse
Let
y=f(x)

Exchange the variables x for y and t for x

Isolate the variable y
![x=\frac{2y+1}{2y-1}\\ \\2xy-x=2y+1\\ \\2xy-2y=x+1\\ \\y[2x-2]=x+1\\ \\y=\frac{x+1}{2(x-1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2y%2B1%7D%7B2y-1%7D%5C%5C%20%5C%5C2xy-x%3D2y%2B1%5C%5C%20%5C%5C2xy-2y%3Dx%2B1%5C%5C%20%5C%5Cy%5B2x-2%5D%3Dx%2B1%5C%5C%20%5C%5Cy%3D%5Cfrac%7Bx%2B1%7D%7B2%28x-1%29%7D)
Let


Part 4) we have

Find the inverse
Let
y=f(x)

Exchange the variables x for y and t for x

Isolate the variable y
![x=\frac{y+2}{-2y+1}\\ \\-2xy+x=y+2\\ \\-2xy-y=-x+2\\ \\y[-2x-1]=-x+2\\ \\y=\frac{-x+2}{-2x-1} \\ \\y=\frac{x-2}{2x+1}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7By%2B2%7D%7B-2y%2B1%7D%5C%5C%20%5C%5C-2xy%2Bx%3Dy%2B2%5C%5C%20%5C%5C-2xy-y%3D-x%2B2%5C%5C%20%5C%5Cy%5B-2x-1%5D%3D-x%2B2%5C%5C%20%5C%5Cy%3D%5Cfrac%7B-x%2B2%7D%7B-2x-1%7D%20%5C%5C%20%5C%5Cy%3D%5Cfrac%7Bx-2%7D%7B2x%2B1%7D)
Let


Part 5) we have

Find the inverse
Let
y=f(x)

Exchange the variables x for y and t for x

Isolate the variable y
![x=\frac{y+2}{y-1}\\ \\xy-x=y+2\\ \\xy-y=x+2\\ \\y[x-1]=x+2\\ \\y=\frac{x+2}{x-1}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7By%2B2%7D%7By-1%7D%5C%5C%20%5C%5Cxy-x%3Dy%2B2%5C%5C%20%5C%5Cxy-y%3Dx%2B2%5C%5C%20%5C%5Cy%5Bx-1%5D%3Dx%2B2%5C%5C%20%5C%5Cy%3D%5Cfrac%7Bx%2B2%7D%7Bx-1%7D)
Let


Number three is the first option
Answer:
The alternative hypothesis will state that there is significant difference between the mean list price of a three bedroom home and the mean list price of a four bedroom home.

Step-by-step explanation:
This would be an two-sample hypothesis test for the difference between two means.
As we are looking for differences, we are not testing if one population mean is bigger than the other. This will be a two-tailed test and the alternative hypothesis will have a unequal sign.
The alternative hypothesis will state that there is significant difference between the mean list price of a three bedroom home and the mean list price of a four bedroom home.
This can be written as:

meaning that the population means are significantly different.
Answer:
Step-by-step explanation:
Prime factorize 121 and 99
121 = 11 * 11
99 = 11 * 3 * 3
Common factor = 11
Answer:
I think its B counterexample
Step-by-step explanation: