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arlik [135]
3 years ago
11

makayla's local movie theater has a movie goer club that charges an annual registration fee of $25. however, movie tickets are d

iscounted for member at $6.00 per ticket, instead of the regular $9.00 per ticket. let m equal the number of movie tickets makayla purchases in a year. write a function to model the amount of money makayla spent on going to the movies during the year she joined the club
Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
<span>C(m) = 6x + 25 would be your answer. </span>
FinnZ [79.3K]3 years ago
5 0

Answer: Our required function is C(m)=25+6m

Step-by-step explanation:

Since we have given that

Cost of tickets per ticket  after discount = $6.00

Amount for registration fee = $ 25

Let m be the number of movie tickets she purchases in a year.

So, the function to model the amount of money she spent on going to the movies during the year is given by

C(m)=25+6m

Hence, our required function is C(m)=25+6m

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Derivative of g(x) = 3x^2(x^2-(2/x))
Elza [17]

When you are doing derivatives, you don't want to do it right away because there is still ( ) we need to remove that first get,

g(x)=3x^4-6x

Now we can do the derivatives!

g(x)=12*x^3 - 6

I hope this helps!

4 0
2 years ago
Select all the expressions which are equivalent to<br> -4/3p - 2/5
AVprozaik [17]

Answer

-2/5 -4/3 p and -4/3p+ (-2/5)

Step-by-step explanation:

those two are the only answers that has both parts of the expressions as negative.

6 0
3 years ago
What's the equation for this problem? Please help!! It's due tomarrow
prohojiy [21]
Wth diaiqowjqksosjshbssbbsjsoaiajw
5 0
2 years ago
Which of the following is equal to the rational expression when x -2 or -6?
kykrilka [37]

The given expression is

f(x) = \frac{3(x+2}{(x+2)(x+6)}

And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2

And a function is undefined when denominator is zero. And at x=-6, denominator become zero.

So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .

4 0
3 years ago
can some one explain to me how fractions work who ever explains it well gets brainliest, adding, subtracting, multiplying, divid
Ludmilka [50]
Adding: When adding fractions, you want to make sure that the denominator is the same for both fractions. If they are already the same, just add both the numerators to get the answer. For example,
\frac{3 }{5}  +  \frac{1}{5}  =  \frac{4}{5}
If the denominator is different in both fractions, you have to find the least common denominator, or LCD. The LCD is the smallest number that both denominators can multiply into. For example, say you need to find
\frac{1}{6}  +  \frac{1}{3}

Multiply both the numerator and the denominator of (1/3) by 2 to get (2/6). This way, the denominators are the same and you can find the answer.
\frac{1}{6}  +  \frac{2}{6}  =  \frac{3}{6}
In the case that one denominator does not go into the other, find the smallest number they both multiply into. For example,
\frac{1}{3 }  +  \frac{1}{4}
Here, the smallest number that both 4 and 3 multiply into is 12. Multiply both fractions by the correct amount to make both denominators 12. It would then become
\frac{4}{12}  +  \frac{3}{12}  =  \frac{7}{12}
Subtraction: follow the same rules as addition, except subtract the numerators instead of adding them.

Multiplication: multiply both numerators and both denominators.
\frac{2}{3}  \times  \frac{4}{5}  =  \frac{8}{15}
Division: Flip one of the fractions and multiply.
\frac{2}{3}   \div   \frac{4}{5}
Becomes
\frac{2}{3}  \times  \frac{5}{4}  =  \frac{10}{12}  =  \frac{5}{6}
Hope this explains it all. Let me know if you have any questions :)
4 0
3 years ago
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