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Amiraneli [1.4K]
2 years ago
11

x}^{2} - 9 \sqrt{2x - 4} " alt=" {x}^{2} - 9 \sqrt{2x - 4} " align="absmiddle" class="latex-formula">
for which value of x is this expression undefined?​
Mathematics
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

When x

Step-by-step explanation:

When x is smaller than 2, the resulting value under the square root will become negative. Since it is impossible to take the root of a negative number, the expression is thus undefined, however, it can be represented with the imaginary number i where i = \sqrt{-1}.

Hope this helps :)

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(2+x)dy/dx=3y need help
den301095 [7]
(2+x) \frac{dy}{dx} =3y
\frac{1}{3y} dy= \frac{1}{2+x} dx
\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx
\frac{1}{3}\ln(3y) = \ln(2+x) + C
(raise both to the power e): e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}
(3y)^ \frac{1}{3} =k(2+x)
3y=k(2+x)^3
y= k(2+x)^3
5 0
3 years ago
Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
We test for the origin because, it is not passing through the origin.

0 \geqslant - (0) + 2
This yields
0 \geqslant 2
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph
8 0
3 years ago
Help ill give brainlest pls
Setler [38]
I the answer To You Problem Is C
6 0
2 years ago
The product 33 × 90 is more than 32 × 90. How much more? Complete the explanation for how you know without multiplying.
Tju [1.3M]

Answer:

90, there are 32 ninetys in 32 X 90 and there are 33 ninetys in 33 X 90, meaning there is one more 90 in 33 X 90 than 32 X 90

5 0
2 years ago
Which graph represents <br> y= -2x?
Kamila [148]
It would be the second graph since the coefficient is negative
5 0
3 years ago
Read 2 more answers
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