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Simora [160]
2 years ago
13

What is the point at which the sun crosses the equator to make night and day the same length during the second time of the year?

Biology
2 answers:
Andru [333]2 years ago
7 0
The point at which the sun crosses the <span>equator to make night and day the same length during the second time of the year is an equinox.</span>
muminat2 years ago
6 0
Equinox
There are 2 each year (March & September) 
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A plant of genotype ccdd is crossed to ccdd and the f1 is testcrossed to ccdd. if the genes are unlinked, what percentage of ccd
amm1812

A plant of genotype ccdd is crossed to ccdd and the f1 is testcrossed to ccdd. if the genes are unlinked, what percentage of ccdd recombinants will result in  0.20255075%

<h3>What is Genotype?</h3>

An organism's genotype is made up of all of its genetic components. The alleles or variations that a person holds in a specific gene or genetic region are also referred to as the genotype.

The amount of copies of each chromosomes found in that species, also known as ploidy, determines how many alleles a person can have for a certain gene. In diploid organisms like humans, there are two complete sets of chromosomes, which means that each person has two different alleles for each gene. Homozygous refers to a genotype where both alleles are the same. Heterozygous refers to a genotype when there are two distinct alleles.

Phenotype, the observable qualities and attributes of an individual or creature, is influenced by genotype.

Learn more about genotype with the help of the given link:

brainly.com/question/5296920

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4 0
1 year ago
If a hemoglobin molecule comes into close contact with a respiring cell, the presence of CO2 in the environment will cause hemog
lapo4ka [179]

Answer:

No, when the concentration of carbon dioxide is high, such as in peripheral tissues, CO2 binds to hemoglobin and the affinity for O2 decreases, causing it to release.

Explanation:

The O2 molecule is reversibly combined with the heme portion of the hemoglobin. When the partial pressure of O2 is high, as in the case of pulmonary capillaries, for example, the binding of O2 to hemoglobin and the release of carbon dioxide are favored, this is known as the Haldane effect. If, on the contrary, when the concentration of carbon dioxide is high, such as in peripheral tissues, CO2 is bound to hemoglobin and the affinity for O2 decreases, causing it to release, this is known as the effect Bohr.

8 0
3 years ago
This is the elliptical orbit of the Earth around the Sun. It takes 365.26 days to complete one orbit.
Strike441 [17]

Answer:

Complete orbit around the Sun takes about 365.26 days. The Earth’s rotation axis is tilted relative to the imaginary space orbit around the Sun.  This imaginary plane is called the ecliptic plane.  Position of northern and southern hemisphere toward the Sun varies depending on the season

Explanation:

6 0
2 years ago
Read 2 more answers
Because Komodo Dragons can reproduce asexually (which only makes females), can Komodo Dragons survive without males?
irina [24]
<h3><u>Answer</u>;</h3>

Yes females can survive without Males

<h3><u>Explanation</u>;</h3>
  • The Komodo dragon can can reproduce sexually or asexually depending on their environmental conditions. At most zoos, females live alone and are kept separate from other dragons.
  • <em><u>The females Komondo dragons can produce babies without fertilization by a male. This process is called parthenogenesis or a virgin conception.</u></em>

8 0
3 years ago
Assume that the genes for tan body and bare wings are 15 map units apart on chromosome II in Drosophila. If a tan-bodied, bare-w
Fittoniya [83]

Answer:

WILD TYPE= 425;

TAN-BARE= 425;

TAN= 75;

BARE= 75

Explanation:

Fifteen map units apart implies that 15% of the offspring are products of recombination.

Out of 1000 offsprings, therefore 15% of 1000= 0.15 × 1000=150

150 offsprings are products of recombination.

100-15 =85%

Therefore, 85% of the offspring are parental.

So, if tan-bodied, ware-winged female was mated with wild-type male resulting in F1 phenotypically wild-type females were mated to tan-bodied, bare-winged males.

The expected number of offsprings that are tanned but have normal wings would be:

Wild type= 50% of 850

0.50 × 850 = 425

Tan-bare= 50% of 850

0.50 × 850 = 425

tan= 50% of 150

0.50×150= 75

Bare= 50% of 150

0.50×150=75

7 0
3 years ago
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