Answer:
Step-by-step explanation:
Let say; By y(x)= y(e)
we have;
Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:
dy/dx = 1/xy
RECALL: y(e) = 3
MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;
Answer:
y=31
Step-by-step explanation:
we know that x=4
5+6(4) = y
5+24 = 31
y= 31
Hoped this helped
A Pythagorean triple is a set of thre integer numbers, a, b and c that meet the Pythgorean theorem a^2 + b^2 = c^2
Use Euclide's formula for generating Pythagorean triples.
This formula states that given two arbitrary different integers, x and y, both greater than zero, then the following numbers a, b, c form a Pythagorean triple:
a = x^2 - y^2
b = 2xy
c = x^2 + y^2.
From a = x^2 - y^2, you need that x > y, then you can discard options A and D.
Now you have to probe the other options.
Start with option B, x = 4, y = 3
a = x^2 - y^2 = 4^2 - 3^2 = 16 -9 = 7
b = 2xy = 2(4)(3) = 24
c = x^2 9 y^2 = 4^2 + 3^2 = 16 + 9 = 25
Then we could generate the Pythagorean triple (7, 24, 25) with x = 4 and y =3.
If you want, you can check that a^2 + b^2 = c^2; i.e. 7^2 + 24^2 = 25^2
The answer is the option B. x = 4, y = 3
The answer is 12
12-(5+3)=4
4+8=12
