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Mama L [17]
3 years ago
11

At the movie theatre, child admission is $6.30 and adult admission is $9.60 . On saturday, twice as many adult tickets as child

tickets were sold, for a total sales of $535.50 . How many child tickets were sold that day?
Mathematics
1 answer:
joja [24]3 years ago
4 0

Let's assume

number of child tickets sold on saturday is x

number of adult tickets sold on saturday is y

On saturday, twice as many adult tickets as child tickets were sold

so, we get

y=2x

child admission is $6.30 and adult admission is $9.60

a total sales of $535.50

we get

6.30x+9.60y=535.50

now, we can plug y=2x

6.30x+9.60*2x=535.50

now, we can solve for x

25.5x=535.5

x=21

now, we can find y

y=2*21

y=42

so,

number of child tickets sold on saturday is 21

number of adult tickets sold on saturday is 42.........Answer


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Answer:

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by \alpha=1-0.96=0.04 and \alpha/2 =0.02. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

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Part b

The margin of error is given by:

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So then if w replace the value of n obtained from part a we got:

ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208    

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