So for this you need the two solutions to be x= -9 and x=3 then move over the numbers and put in brackets (x+9)(x-3) then multiply together x^2+9x-3x-27 then combine like terms to get x^2+6-27
2x + 3y = 6
3y = - 2x + 6
y = -2/3x + 2....slope here is -2/3
A parallel line will have the same slope
y = mx + b
slope(m) = - 2/3
(-2,3)...x = -2 and y = 3
now we sub, we r looking for b, the y intercept
3 = -2/3(-2) + b
3 = 4/3 + b
3 - 4/3 = b
9/3 - 4/3 = b
5/3 = b
ur equation is : y = -2/3x + 5/3 (slope intercept form)
y = -2/3x + 5/3
2/3x + y = 5/3
2x + 3y = 5 (standard form)
Answer:
A: Since disjoint, P(up AND up AND up) = P(up) P(up) P(up) = .653= .27
A: Disjoint, so previous years have no effect on this year. 1-.65 = .35
A: Same direction; two different probabilities. P(up AND up) = .652 = .42. P(down AND down) = .352= .12. .42 + .12 = .55
Step-by-step explanation:
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
