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kozerog [31]
2 years ago
9

The questions are in the picture (I’LL GIVE BRAINLEST) PLEASEEEEEEEEEEE HELPPPPPPP

Mathematics
1 answer:
PIT_PIT [208]2 years ago
8 0

Answer:

i think part A

1)3:2

2)3:4

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8+6q+q in a word expression
GarryVolchara [31]
Well,

8 + 6q + q

We could be lazy and not simplify this.  Thus, we would say:
"Eight plus 6 times a number q plus q."

Or, we could be smart, collect like terms, and say:
"Eight plus 7 times a number q."
3 0
3 years ago
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The ages of the members of a gym have a mean of 4747 years and a standard deviation of 1111 years. what can you conclude from​ c
Bond [772]

Chebyshev came up with the limits on how much or how many of the data must lie close to the mean. In specific for any positive k, the proportion of the data that lies within k standard deviations of the mean is at least: <span>

1 - 1/k² 

<span>In this problem  the mean is 47 yrs therefore:

(47 – 17.3) = 29.7 = (76.7 - 47) </span></span>

The value of k is calculated using the formula:<span>

29.7 / 11 = 2.7 = k</span>

So the % of gym members aged between 19.4 and 76.6 is: <span>

1 - 1 / (2.6)² = 0.863 = 86.3 %</span>

 

<span>Therefore 86.3% of the gym members are aged between 19.4 and 76.6</span>

5 0
3 years ago
Mr. and Mrs. Pierotti are remodeling their kitchen. They need 9 square yards of covering for the floor. Jackson Interiors quoted
meriva
Carpet Master would be cheaper because 6 x 9 would be 54 $$$
7 0
3 years ago
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To solve n+7=15 you should first
sertanlavr [38]

Answer:

  1. Collect like terms and simplify
  2. Subtract 7 from both sides

Step-by-step explanation:

METHOD 1

n+7=15\\n =15-7\\n = 8

METHOD 2

n+7-7=15-7\\n =8

7 0
3 years ago
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The weights of NCAA lacrosse players are approximately normally distributed with a mean of 182 lbs and a standard deviation of 1
Marizza181 [45]

Answer:

What can I do for you

Step-by-step explanation:

4 0
2 years ago
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