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2 years ago

What is the best estimate for the product of 287 and 7

1 answer:

6 0

Well, product is the answer to a multiplication problem. So, first you multiply 287 × 7, which equals 2,009. The estimate would be 2,000.

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a game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you

nadezda [96]

Yes, I would play the game, because the probability of winning is 13/18.

Probability:

Probability refer the possible occurrence of any particular event.

Given,

A game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you lose a dollar.

Here we need to find whether we able to play this one or not.

To find that one, first, we have to identify the winning scenarios,

Let us consider five winning scenarios. Lets represent the dice outcomes as A, B, C, and D, where your dice are A and B and the other player's are C and D. The five scenarios are:

1) A = B

2) A = C

3) A = D

4) B = C

5) B = D

We know that the total possible outcomes is 6^4. We can go through each scenario and count the possible outcomes. We must be careful to avoid overcounting.

Based on this,

The probability that none match is

=> 6*5*4*3/6^4

=> 360 / 1296

=> 5 / 18

So, probability of winning is,

=> 1 - 5/18

=> 13/18.

So, based on the probability the chance of winning is high. So, we can play it.

To know more about Probability here.

brainly.com/question/11234923

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5 0

1 year ago

3.26 round to the nearest tenth

zaharov [31]

It's 3.3 because the 2 is in the tenths place and you look at 6 and say is it over 5? Yes it is so the next number after 2 is 3 so your answer is 3.3

7 0

3 years ago

Read 2 more answers

If ,f(x)=3x-6/x-2 what is the average rate of change of f(x) over the interval [6, 8]?

sukhopar [10]

I hope this helps you

f (x)= 3 (x-2)/(x-2)

f (x)= 3

f(6)= 3

f (8)= 3

4 0

3 years ago

Read 2 more answers

Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11

slavikrds [6]

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,

103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +

xlim(c(70, 120)) +

scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

7 0

2 years ago

Fiona wrote the linear equation y = 2/5 X -5. When Henry wrote his equation they discovered that his equation had all the same S

REY [17]

The equation of the graph is given as y = (2/5)x - 5.

You have to figure out which of the choices equals the equation given,
y = (2/5)x - 5.
You could solve each of the answer choices for y, but since each choice is in the format x - (m)y = b, you can put the given equation in that format too.

$y= \frac{2}{5}x - 5 \\ 
5= \frac{2}{5}x-y \\ 
 \frac{2}{5}x - y = 5 \\ 
 (\frac{5}{2}) \frac{2}{5}x - (\frac{5}{2})y = (\frac{5}{2})5 \\ 
x - (\frac{5}{2})y = \frac{25}{2}$

5 0

2 years ago

Read 2 more answers