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docker41 [41]
3 years ago
15

80 is 1/10 of what???do you know

Mathematics
2 answers:
Viktor [21]3 years ago
5 0
800.................
SOVA2 [1]3 years ago
3 0
Hi! The answer is 800 Glad To Help! :-D 
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Jose and a group of friends bought concert tickets for $257. The booking agency also charged a fee, bringing the total cost to $
Art [367]

Answer: hello there here is your answer:

7%

Step-by-step explanation:

if you divide the difference between the two numbers it will give you a decimal ....you need to convert that decimal into a percent which is 7%

hope this help have a good day bye

4 0
3 years ago
For which situation could flipping a coin be used to simulate a random sample?
Margaret [11]
When your measuring a possibility of two different outcomes
7 0
3 years ago
Maria boards boards a car at the bottom of a ferris wheel. she rides to the top and then it stops. maria tells her friends they
DaniilM [7]

Maria is wrong because they have completed 1/2.

Step-by-step explanation:

At the top of the Ferris wheel,the ride is 1/2 done. All that is left is to go down,which is the other half. Maria is wrong in saying they are 1/4 done,that is a quarter,not half.

6 0
3 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
1 year ago
Katy's favorite rides at the amusement park are the roller coasters and water slide. The wait time for the roller coaster is 25
ioda

Answer:

She went on the slide 8 times and on the roller coaster 4 times

Step-by-step explanation:

We convert each statements to a mathematical equation.

Firstly, let's represent the number of times she went on the coaster with R and the number of times on the slide with S. We know quite well she went on 12 rides. Hence the summation of both number of times yield 12.

Mathematically, R + S = 12. ........(i)

Now we also know her total wait time was 3hours. Since an hour equals 60 minutes, her total wait time would equal 180 minutes.

To get a mathematical representation for the wait time, we multiply the number of roller coaster rides by 25 and that of the slides by 10.

Mathematically, 25R + 10S = 180 .......(ii)

Here we now have two equations that we can solve simultaneously.

From equation 1 we can say R = 12 - S. We can then substitute this into equation 2 to yield the following:

25(12 - s) + 10s = 180

300 - 25s + 10s = 180

300 - 25s + 10s = 180

300 - 15s = 180

15s = 300 - 180

15s = 120

S = 120/15

S = 8

S = 8 , and R = 12 - S = 12 - 8 = 4

7 0
3 years ago
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