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Goshia [24]
2 years ago
14

PLEASE HELP! I HAVE A TIME LIMIT AND IM BEHIND

Mathematics
1 answer:
Kipish [7]2 years ago
3 0

Answer:

Part A none

Part B drawn

Step-by-step explanation:

Suppose the transversal intersects a pair of parallel lines it creates two pairs of alternate exterior angles.

Now if we look at the first figure we find that the alternate exterior angle 1 and 4 are equal . Also 3 and 2 are equal.

But <1 and < 2 are not equal . They are supplementary angles. Their sum is equal to 180 degrees.

Similarly angles 3 and4 are supplementary angles.

This situation does not support Ricky's claim. So you will select none in part A.

Now in part B we see that angle 5 &8 are equal and 6 & 7 are congruent.

This refutes Ricky's claims and this can be proved mathematically.

Angles 5 & 6 are supplementary angles. Similarly 7 & 8 are supplementary therefore they cannot be equal as they are unequal and a transversal is drawn not a perpendicular.

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Step-by-step explanation:

\sf y = \frac{2}{3} x+4

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make y the subject in equation 2:

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insert this in equation 1:

\sf \frac{24-2x}{3} =\frac{2}{3} x+4

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solve for y:

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\sf y = \frac{24-2(3)}{3}

\sf y =6

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