Answer:
A person can select 3 coins from a box containing 6 different coins in 120 different ways.
Step-by-step explanation:
Total choices = n = 6
no. of selections to be made = r = 3
The order of selection of coins matter so we will use permutation here.
Using the formula of Permutation:
nPr = 
We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.
Order of coin is important means that if we select 3 coins in these two orders:
--> nickel - dime - quarter
--> dime - quarter - nickel
They will count as two different cases.
Calculating the no. of ways 3 coins can be selected from 6 coins.
nPr = = 
nPr = 120
Answer:
h(-4) = -4
Step-by-step explanation:
Since x is given (x = -4). Then, all you need to do is log in -4 for each value of x
h(-4) =
−
(
−
4
)
2
-3(-4)
h(-4) = -(16) + 12 = -4
Step 1:
In a sample of 380 randomly selected reservations, 19 were no-shows.
Step 2:
Proportion of no shows p<0.06.
Step 3:
Test Value
z(19/380)=0.05
Step 4:
Test statistics
a) 0.05-1.124=-1.074
b) 0.05-(-1.943) = 0.05+1.943=1.993
c)0.05-(-0.821)=0.05+0.821=0.871
d)0.05 - 0.222 = - 0.172
e)0.05 -(-1.571) = 0.05+1.571 = 1.621
The above data clearly mentions the test statistics associated with the given samples.
X=-33 y= 10
Leave first row the same multiply 2nd row by -1
-2x+8y=14
2x+2y=26
10y= 40
Y=4
-2x+8(10)=14
-2x+80=14
Answer:
3
Step-by-step explanation:
