Question

Line j passes through points (-6,1) and (-3,6) .line m is parallel to line j and passes through point (15,-1). what is the equation of line m ?

Answer 1

Slope of line j;
m=$\frac{change in x}{change in y}$
m=$\frac{6-1}{-3--6}$
m=$\frac{5}{3}$
Parallel lines have equal gradients;
So, 
y=mx+c
y=5/3x+c
Replacing for x and y;
-1=5/3(15)+c
-1=25+c
c=-26
y=$\frac{5}{3} x-26$