If x is 32 mm what’s the area of the triangle

Mathematics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

4608*sqrt(3)

Step-by-step explanation:

x + 2x = 3x, so 3x is the height of the triangle. This is a 90-60-30 triangle so the base would be 3x*sqrt(3). To find the area, we can multiply the base with the height and divide by two, so it would be (3x)(3x*sqrt(3))/2 or (9/2)x^2 * sqrt(3). x = 32, and plugging this into the equation gets us to (9/2)32^2 * sqrt(3), which is 4608*sqrt(3).

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Help! How would I solve this trig identity?

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Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

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Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

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