3. Use >, < or = to solve the inequality below. 4/51/2

(a) What is the equation of the line, written in slope-intercept form? Show how you determined the

lutik1710 [3]

Answer:

Step-by-step explanation:

6 0

4 years ago

Find the sum of the polynomials. (3x3 + 4x2 - 2x + 1) + (x4 - x3 + 5x2 + 2x + 3) A. x4 + 2x3 + 9x2 - 4x + 4 B. x4 + 4x3 + 9x2 +

alisha [4.7K]

$3 x^{3} + 4 x^{2} -2x + 1 + x^{4} - x^{3} + 5 x^{2} + 2x +3 = x^{4} +2 x^{3} + 9 x^{2} + 4$

Hence, the answer is D.

7 0

4 years ago

Solve equation 2(4b-6)=4(3b-7)

iren [92.7K]

Answer:

2(4b - 6) = 4(3b - 7)

This is

8b - 12 = 12b - 28

Now,

16 = 4b

This means that b = 4 :)

5 0

3 years ago

Read 2 more answers

If x is an even integer greater than 3, then, in terms of

prisoha [69]

Answer:

x^2

Step-by-step explanation:

Any even number raised to two is even.

Eg: 4^2 = 16

12^2 = 144

Etc...

And

Any odd number raised to two is odd.

Eg: 5^2 = 25

13^2 = 169

Etc...

And also x^2 is greater than 2x & x+3 & x+2

6 0

2 years ago

A poll found that 52% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.

Leya [2.2K]

Answer:

The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is (0.46, 0.58). This means that we are 99% sure that the true proportion of all U.S. adult Twitter users who get some news on Twitter is between these two values.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A poll found that 52% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.4%

This means that:

$\pi = 0.52, \sqrt{\frac{\pi(1-\pi)}{n}} = 0.024$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 - 2.575(0.024) = 0.46$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 + 2.575(0.024) = 0.58$

The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is (0.46, 0.58). This means that we are 99% sure that the true proportion of all U.S. adult Twitter users who get some news on Twitter is between these two values.

8 0

3 years ago