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3 years ago

Explain how you would find the sum of 46+7

Mathematics

2 answers:

tankabanditka [31]3 years ago

8 0

You add the numbers up so 53

MissTica3 years ago

6 0

Line up the answers 46 on top, 7 on bottom, 7 should be on right by the way. Then add up to down, boom there's your answer. 53

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If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750

maksim [4K]

Answer:

$\boxed {\boxed {\sf 250 \ people}}$

Step-by-step explanation:

Let's set up a proportion using the following setup.

$\frac {buses}{people}=\frac {buses}{people}$

We know 30 buses can carry 1,500 people.

$\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}$

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

$\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}$

$\frac {30 }{1500 }=\frac {5 }{x }$

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

$30*x=1500*5\\30x=7500$

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

$30x/30=7500\\x=250$

5 buses can carry 250 people.

7 0

3 years ago

Write the ratio as a fraction in simplest form 25 to 45

brilliants [131]

Answer:

5/9

Step-by-step explanation:

3 0

3 years ago

Solve <br> x^3 - 3x^2 - 13x + 15=<br> x^4 + 3x^3 - 8x^2 + 5x - 25=<br> x^3 - 2x^2 - x + 2 =

AleksAgata [21]

We have Been doing Solving qart log

5 0

3 years ago

Find the arc length of the curve on the given interval. Parametric Equations Interval x = 6t + 5, y = 7 − 5t −1 ≤ t ≤ 3

laiz [17]

Answer:

31.241

Step-by-step explanation:

x = 6t + 5, y = 7 − 5t −1 ≤ t ≤ 3

dx/dt = 6

dy/dt = -5

The arc length of the curve can be calculated below as

L = ∫ $\sqrt{(\frac{dx}{dt} )^2 + (\frac{dy}{dt})^2 dt }$

= $\int\limits^3_ {-1} \, \sqrt{36 + 25 dt}$

= $\sqrt{61} \int\limits^3_ {-1} \, dt$

= $\sqrt{61} [3-(-1)]$

= 4 $\sqrt{61}$ = 31.241

8 0

3 years ago

Suppose that time spent on hold per call with customer service at a large telecom company is normally distributed with a mean µ

lana66690 [7]

Answer:

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 minutes

Standard Deviation, σ = 2.5 minutes

Sample size, n = 25

We are given that the distribution of time spent is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{2.5}{\sqrt{25}} = 0.5$

P(sample mean is between 7.8 and 8.2 minutes)

$P(7.8 \leq x \leq 8.2)\\\\ = P(\displaystyle\frac{7.8 - 8}{0.5} \leq z \leq \displaystyle\frac{8.2-8}{0.5})\\\\ = P(-0.4 \leq z \leq 0.4})\\\\= P(z < 0.4) - P(z < -0.4)\\\\= 0.6554 -0.3446= 0.3108$

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

4 0

3 years ago