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Inga [223]
3 years ago
9

How to convert 1.2 into a fraction

Mathematics
1 answer:
slega [8]3 years ago
5 0
If you're placing the the decimal over the power of 10 then i think your answer is 6/5
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I NEED HELP!!!!!!! due in 10 min PLZZZZZ!!!!
Mama L [17]

Answer:

-3, 6, 7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
Match each equation with its solution.
Aleksandr-060686 [28]

Answer:the first one is ten And the last one is the first one on top

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
2.5(6x -4) = 10+4(1.5+0.5x)
Lemur [1.5K]

Answer:

x = 2

Nothing more, nothing less

6 0
3 years ago
The difference of two numbers, a and b, is 21. The difference of 5 times a and two times b is 18. What are the values of a and b
zheka24 [161]

Answer:

E.  -8, -29

Step-by-step explanation:

a-b=21

5a -2b =18

Take the first equation and solve for a by adding b to each side

a-b=21

a-b+b=21+b

a = 21+b

Now substitute a=21+b into the second equation

5a -2b =18

5(21+b) -2b =18

Distribute the 5

105 +5b-2b =18

Combine like terms

105 +3b =18

Subtract 105 from each side

105-105 +3b = 18-105

3b = -87

Divide each side by 3

3b/3 =-87/3

b = -29

if b = -29, we can substitute it into a =21+b

a = 21-29

a = -8

5 0
3 years ago
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