A like with slope = 1/2 passes through the points (2,5) and (x,3). What is the value of x?

1 answer:

8 0

Y = mx + b

slope = m = 1/21, so we have

y = 1/2 x + b

The line passes through (2, 5), so we get

5 = 1/2 * 2 + b

5 = 1 + b

b = 4

The equation of the line is

y = 1/2 x + 4

Point (x, 3) has a y-coordinate of 3. We are looking for the x-coordinate.

y = 1/2 x + 4

3 = 1/2 x + 4

-1 = 1/2 x

x = -2

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Please help! I can't seem to figure this stuff out...

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1: always rearrange the equation to y = mx + c so....
x - y = o

x = y

So the gradient is 1 and it intersects the y axis at (0,0)

The three points could be (1,1), (2,2), (3,3) and so on

2: -x -2y = -10
Multiply everything by -1

x + 2y = 10

2y = 10 - x

y = 5 - x/2

The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on

3: x + y = -2

y = -2 - x

The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on

4: -3y =-x -7

Multiply everything by -1

3y = x + 7

y = x/3 + 7/3

The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o

5: -y = -x + 1

y = x - 1

The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on

Hope this helps! Any questions let me know :)

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