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Akimi4 [234]
3 years ago
9

An illusionist needs up to 10 volunteers for a show. She needs no fewer than 4 female volunteers. Let x represent the number of

female volunteers and y represent the number of male volunteers.
Which inequalities model the situation?
Select all inequalities that model this situation.

A- x + y < 10
B- x + y ≤ 10
C- x > 4
D- x ≥ 4
E- y > 0
G- y ≥ 0
Mathematics
2 answers:
Sliva [168]3 years ago
7 0

The <em><u>correct answers</u></em> are:

B- x + y ≤ 10 ; and D- x ≥ 4

Explanation:

The illusionist needs at least 4 female volunteers.  This means he could use 4 or more; this means x, the number of female volunteers, is greater than or equal to 4:

x ≥ 4

The total of number of volunteers needed is up to 10.  This means the illusionist can use 10 or fewer people; this means the total is less than or equal to 10.

The number of female volunteers is x and the number of male volunteers is y; together they create the expression x+y.  This gives us

x+y ≤ 10

iogann1982 [59]3 years ago
6 0
B, D, and E are all inequalities that model the situation
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Step-by-step explanation:

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Step-by-step explanation:

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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

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x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
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melisa1 [442]

Answer:

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Step-by-step explanation:

Given:

The system of equations to solve is given as:

y=2x\\\\x+y=-6

In order to solve this system of linear equations, we use substitution method.

In substitution method, we substitute the value of any one variable in the other equation.

So, we substitute the value of 'y' from first equation in the second equation.

This gives,

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Dividing both sides by 3, we get:

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Now, y=2x=2\times -2=-4

Therefore, the solution is (-2, -4)

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