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Bad White [126]
3 years ago
7

Which fractions are equivalent to 4/9? Choose Yes or No for each fraction. Please answer quickly i need this!

Mathematics
2 answers:
mamaluj [8]3 years ago
6 0
8/18 and 36/81 are equivalent
kupik [55]3 years ago
4 0

Answer:

no,yes,no,yes

Step-by-step explanation:

8/18 and 12/27. thank me later. By the way, you should start studying.. rather than not knowing the easy questions lol

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Below are monthly rents paid by 30 students who live off campus. 730 730 730 930 700 570 690 1,030 740 620 720 670 560 740 650 6
Gennadij [26K]

Answer:

the answer is to add up all the numbers.

Step-by-step explanation:

7 0
3 years ago
Help me plz, i dont pay alot of attention in class
artcher [175]
What I did was add all the x's since you are trying to find the perimeter then I got 16 and then you add the whole numbers. 16x+3
5 0
2 years ago
Read 2 more answers
It takes levar four hours to drive 252 miles what is levar unit rate at this rate how far will Levar Drive in seven hours
otez555 [7]
In four hours, he drives: = 252

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Hope this helps!
5 0
2 years ago
Variable Terms in 3x + 2 – 10 – 3x
ratelena [41]

Answer:

X

Step-by-step explanation:

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6 0
2 years ago
1. Based on the information given, can you determine that the quadrilateral must be a
zhenek [66]

<u>Solving Q1: Given BE = ED and AE = EC.</u>

Considering triangles ΔAED and ΔCEB;

1. AE = EC (given)

2. ∠AED = ∠CEB (vertical angles)

3. ED = EB (given)

ΔAED ≡ ΔCEB (Side-Angle-Side congruency of triangles)

∠DAE = ∠BCE and AD = BC (using CPCTC)

⇒ AD║BC (Converse of Alternate Interior angles theorem)


Similarly consider triangles ΔABE and ΔCDE;

1. AE = CE (given)

2. ∠BEA = ∠DEC (vertical angles)

3. BE = DE (given)

ΔABE ≡ ΔCDE (Side-Angle-Side congruency of triangles)

∠ABE = ∠CDE and AB = CD (using CPCTC)

⇒ AB║CD (Converse of Alternate Interior angles theorem)


Since we have AB║CD, AB = CD and AD║BC, AD = BC.

Therefore, quadrilateral ABCD is a parallelogram.

****************************************************************************************************

<u>Solving Q2: The parallelogram has the angle measures shown in the diagram.</u>

It is clearly visible that both the triangles are Isosceles triangles, so opposite sides in each triangle are equal.

Consider two triangles given in the problem, we have two sets of congruent angles and one included side is common in both triangles.

Using Angle-Side-Angle congruence of triangles, both the triangles would be congruent too.

Using CPCTC, we can say opposite sides of quadrilateral would be congruent.

Therefore, all sides in given quadrilateral are equal.

Hence, Given quadrilateral is a Rhombus.

7 0
3 years ago
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