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zubka84 [21]
3 years ago
6

Complete the table for the given rule. Rule: y is 2 more than 4 times 2 pls help

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0

Answer:

[2,10,18]

y = 4x + 2

0,2

1,6

2,10

3,14

4,18

Step-by-step explanation:

tensa zangetsu [6.8K]3 years ago
7 0

Answer:

x=0  y=2

x=2  y= 10

x=4  y= 18

Step-by-step explanation:

Is means equals

y = 4x+2

Let x = 0

y = 4(0)+2 = 2

Let x = 2

y = 4(2)+2 = 8+2 = 10

Let x =4

y = 4(4)+2 = 16+2 = 18

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Mila [183]
I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

\sf ax^2+(1-a(b+c))x+abc-d)

\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))

Simplify into standard form:

\sf x^2+(1-1(5))x+6-4

\sf x^2+(1-5)x+2

\sf x^2-4x+2

Use the quadratic formula to solve:

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

For functions in the form of \sf ax^2+bx+c. So in this case:

a = 1
b = -4
c = 2

Plug them in:

\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}

Solve for 'x':

\sf x=\dfrac{4\pm\sqrt{16-8}}{2}

\sf x=\dfrac{4\pm\sqrt{8}}{2}

\sf x\approx\dfrac{4\pm 2.83}{2}

\sf x\approx 0.59,3.41

So the answer would be A.
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