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bearhunter [10]
3 years ago
7

A/b=c/d solve for aPLEASE HELP

Mathematics
1 answer:
Molodets [167]3 years ago
3 0
A = C. Msg if u need more help :3
You might be interested in
Annette drove through an intersection without looking and hit Vincent's car that he had driven into the intersection without obe
Karolina [17]

Answer:

$80,000

Step-by-step explanation:

Under a Comparative negligence theory, people involved in an accident are entitled to compensation according to their contributions towards the accident. In this case, Annette contributed 20% to the collision and, thus, should receive 100% - 20% of her total loss determined by the jury. Annette should be awarded:

A= \$ 100,000*(1-0.2)\\A=\$ 80,000

Therefore, the jury should award Annette $80,000

7 0
3 years ago
Plz help
Angelina_Jolie [31]

Answer:

Part A

The two equations are;

d = 3 m/s × t for Boat A

d = 4.8 m/s × (t - 6 s) for Boat B

Part B

The solution to the system of equation are

t = 16 s and d = 48 m

Part C: The possible values of 't' for Boat A are 0 ≤ t ≤ ∞

The possible values of 't' for Boat B are 6 ≤ t ≤ ∞

Boat B timing starts when Boat B crosses the start line when t = 6 seconds

The solution of the system of equation indicates that Boat B and Boat A arrive at the same point, 'd' 48 meters from the start, 16 seconds from the time Boat A crosses the stat line

Step-by-step explanation:

The given parameters are;

The speed of Boat A = 3 m/s

The speed of Boat B = 4.8 m/s

The time Boat B crosses the start line = 6 seconds after Boat A crosses the start line

Part A

The two equations are;

For Boat A

d = 3 m/s × t...(1)

For Boat B

d = 4.8 m/s × (t - 6 s)...(2)

Where;

t = The time in seconds since Boat A crossed the start line

d = The distance traveled by the boat in meters

Part B

The system of equations from Part A is solved as follows;

d = 3 m/s × t and d = 4.8 m/s × (t - 6 s)

At the (common) solution point to the system of equation, we have;

d = 3 m/s × t, d = 4.8 m/s × (t - 6 s)

∴ 3 m/s × t = 4.8 m/s × (t - 6 s)

3·t m/s  = 4.8·t m/s - 28.8 m

3·t m/s + 28.8 m = 4.8·t m/s

4.8·t m/s = 3·t m/s + 28.8 m; By transitive property of equality

4.8·t m/s - 3·t m/s = 28.8 m

1.8·t m/s = 28.8 m

t = 28.8 m/(1.8 m/s) = 16 s

t = 16 s.

d = 3 m/s × t = 3 m/s × 16 s = 48 m

d = 48 m

The solution of the system of equation is t = 16 s, d = 48 m

Part C: The possible values of 't' for Boat A are 0 ≤ t ≤ ∞

The possible values of 't' for Boat B are 6 ≤ t ≤ ∞

The timing variable, 't' for the equations of Boat A and Boat B is with reference to the time which Boat A crosses the start line, which is 6 seconds before Boat B, therefore, Boat B crosses the start line when t = 6 seconds

The solution of the system of equation represents that Boat B reaches Boat A at a point 48 meters from the start, 16 seconds from the time Boat A crosses the stat line.

4 0
3 years ago
5 2/3 divided by what is 1?
strojnjashka [21]

Answer:

5 2/3

Step-by-step explanation:

I'm not sure how to explain, but 5 2/3 divided by itself is 1...

I hope this helped a little bit still. Have a great day c:

5 0
3 years ago
Read 2 more answers
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Please help i’ll give brainless
mixas84 [53]
You wanna simplify the expression first
5(3m+2p+m)
=15m+10p+5m
so B would be correct
8 0
3 years ago
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