Answer:
180, 180, 148, 180, 148
Step-by-step explanation:
The two rules in play here are ...
- the sum of interior angles of a triangle is 180°
- the angles of a linear pair are supplementary (they total 180°)
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The first of these rules answers the first two questions:
- interior angles total 180°
- angles 1, 3, 4 total 180°
We can subtract the measure of angle 1 from both sides of the previous equation to find the sum of the remaining two angles.
- angles 3 and 4 total 148°
The second rule answers the next question:
- angles 1 and 2 total 180°
As before, subtracting the value of angle 1 from both sides of the equation gives ...
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<em>Additional comment</em>
Of course, the subtraction property of equality comes into play, also. For some unknown, X, you have (in both cases) ...
X + 32° = 180°
X +32° -32° = 180° -32° . . . . . . subtraction property of equality
X = 148° . . . . . . . . simplify
In the first case, X is the sum of angles 3 and 4. In the second case, X is angle 2 only.
From my calculations I got :
- 24 pints of blue paint
- 16 pints of red paint
Answer:
a = 5 or a = -5
Step-by-step explanation:
10. 10
11. -2.8
Hope u enjoyed xD
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation: