A=43°
B=82°
c=28
1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
125°+C=180°
Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
C=55° (option B or C)
2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°
2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3
2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8
Answer: Option B) C=55°, b=33.8, a=23.3
Rewrite the fractions to have a common denominator:
1/3 = 10/30
4/6 = 20/30
1/5 = 6/30
Now compare the numerators and list from smallest to largest:
6/30, 10/30, 20/30
The order would be:
1/5, 1/3, 4/6
Answer:
5 gallons of water must be added.
10 gallons to start with
adding 'x' gallons of water final volume = 10 + x
.9 (10) = amount of vinegar
.1(10) = amount of water
amount of vinegar before and after water addition is constant
.9(10) = .6(10+x)
9 = 6 + .6x
3 = .6x
x = 5 gallons of water to be added
(i truly hope i helped you
Answer:
the answer is -p-30
Step-by-step explanation:
first you would distribute -5 to p and 6 = 4p-5p-30
second combine the like terms = -p-30
lastly it cannot be factored down any farther so the answer is just -p-30
Answer:
The second amount is 3.72
Step-by-step explanation:
Given
Required
Find Second
Substitute 9.92 for First
Express as fraction
Multiply both sides by 9.92
