Answer:
7k + 5s = y
v = k + s
Step-by-step explanation:
Translate the statements into equations. We can use 'x' for dimes and 'y' for quarters.
"<span>A boy has 11 coins in dimes and quarters"
![\sf x+y=11](https://tex.z-dn.net/?f=%5Csf%20x%2By%3D11)
"</span><span>Their value is $1.70"
</span>
![\sf 0.10x+0.25y=1.70](https://tex.z-dn.net/?f=%5Csf%200.10x%2B0.25y%3D1.70)
<span>
To solve this, we can first solve for one of the variables in the first equation, and then plug that into the second equation:
![\sf x+y=11](https://tex.z-dn.net/?f=%5Csf%20x%2By%3D11)
Subtract 'x' to both sides:
![\sf y=11-x](https://tex.z-dn.net/?f=%5Csf%20y%3D11-x)
Now plug this value of 'y' into the second equation:
</span>
![\boxed{\sf 0.10x+0.25(11-x)=1.70}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%200.10x%2B0.25%2811-x%29%3D1.70%7D)
So this equation could be used to solve the problem.
Answer:
V=167.5 cubic mm
Step-by-step explanation:
Volume of the Cone is given with the formula
![V=\frac{1}{3} \pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2h)
though we are not specified what is radius and which one is the height , we are assuming that ,
Height = 10 mm
Radius = 4 mm
Substituting these values in the formula we get
![V=\frac{1}{3} \pi 4^2 \times 10](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%204%5E2%20%5Ctimes%2010)
![V=\frac{1}{3} \pi 160](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20160)
![V=\frac{160 \times 3.14}{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B160%20%5Ctimes%203.14%7D%7B3%7D)
![V=\frac{160 \times 3.14}{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B160%20%5Ctimes%203.14%7D%7B3%7D)
![V=\frac{502.40}{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B502.40%7D%7B3%7D)
![V=167.5](https://tex.z-dn.net/?f=V%3D167.5)
Area of a triangle = 1/2 base * height
A = 1/2 (10)* 20
A= 5*20
A = 100 cm^2
Choice C
(21+39a)/20. Because they have to have the same denominator