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siniylev [52]
3 years ago
5

Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0
Its 2 km hope this help have a nice day
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Analyze the diagram below and complete the instructions that follow.
Ratling [72]

Answer:

your answer is c

Step-by-step explanation:

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3 years ago
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Hi I need help on this I've been working on it for about 20 minutes now please help :)
Mama L [17]

Answer:

V = 4 2/3 units ^3

Step-by-step explanation:

We are given the area of the back rectangle

V = BH where B is the area of the base

V = 3 1/3 * 1 2/5

Rewriting the mixed numbers as improper fractions

V = 10/3 * 7/5

V = 70/15

Simplifying

V = 14/3

Changing back to a mixed number

V = 4 2/3 units ^3

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2 years ago
Heres the picture, thank you!
Arte-miy333 [17]
Leg * /2 = hypotenuse
Hypotenuse divided by /2 = leg

12 divided by /2

Rationalize denominator:
12 * /2 divided by by /2 * /2

Simplify denominator:
12 * /2 divided by 2

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6 * /2 or 4.24

Both x and y because it’s a 45-45-90 triangle
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3 years ago
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Identify any solutions to the system shown here.
OLga [1]
The answer would be B and D.  This can be found by putting the x and y values into the inequality to find whether or not they are true.

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3 years ago
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A wallet contains $460 in $5, $10, and $20 bills. The number of $5 bills exceeds twice the number of $10 bills by 4, and the num
Butoxors [25]

Answer:

Number of $5 bills = 32

Number of $10 bills = 14

Number of $20 bills = 8

Step-by-step explanation:

Let x number of $5, y number of $10 and z number of $20

The number of $5 bills exceeds twice the number of $10 bills by 4.

Therefore, x = 2y + 4

The number of $20 bills is 6 fewer than the number of $10 bills.

Therefore, z = y - 6

A wallet contains $460 in $5, $10, and $20 bills.

Therefore,

5x + 10y + 20z = 460

Substitute x and y into equation

    5(2y+4) + 10y + 20(y-6) = 460

10y + 20 + 10y + 20y - 120 = 460

                           40y - 100 = 460

                                    40y = 460 + 100

                                    40y = 560

                                      y = 14

  • Put the value of y into x = 2y + 4 and solve for x

                                      x = 2(14) + 4

                                      x = 32

  • Put the value of y into z = y - 6 and solve for z

                                      z = 14 - 6

                                      z = 8

Hence, the each type of bills,

Number of $5 bills = 32

Number of $10 bills = 14

Number of $20 bills = 8

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3 years ago
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