3 years ago

Evaluate (-3)(5) I really am not that good at math..someone help

Mathematics

1 answer:

trasher [3.6K]3 years ago

8 0

I’m not really sure

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100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).

victus00 [196]

Answer:

The value of $h^\prime(1)=5$

Step-by-step explanation:

Given that $h(x)=f(f(x))$

now to find $h(x)=f(f(x))$ from the given functions f(x) and f'x

let $h(x)=f(f(x))$

Then put x=1 in above function we get

$h(1)=f(f(1))$

$=f(3)$ (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

$h^{\prime}(x)=f^{\prime}(f^\prime(x))$ (since $h(x)=f(f(x))$ )

put x=1 in above function we get

$h^{\prime}(1)=f^{\prime}(f^\prime(1))$

$=f^{\prime}(2)$ (From the table $f^\prime(1)=2$ and $f^\prime(2)=5$ )

$h^{\prime}(1)=5$

Therefore $h^{\prime}(1)=5$

4 0

3 years ago

Read 2 more answers

Help please what is

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

#SPJ10

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