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3 years ago

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which of the following is the equation of a line with a slope of -5/9 and passing through the point (9,6)

1 answer:

polet [3.4K]3 years ago

7 0

Given the slope and a point on the line, use the point-slope formula for the equation of a straight line.

y-6 = (-5/9)(x-9)

This can be put into other forms. For example,

Multiplying all terms by 9 results in 9y - 54 = -5(x-9) = -5x + 45

Solving for y: 9y - 54 = -5x + 45
+54 = +54
---------------------------
9y = -5x + 99

Then y = (-5/9)x + 11.

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3 years ago

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Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

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Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

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$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

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Answer:

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So the third one is incorrect

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