Local(L) = 1 x (15.99)
Online(O) = (1 x 13.99) + 6
So use that equation until you find the same number.
L1=15.99
O1=19.99
L2=31.98
O2=33.98
L3=47.97
O3=47.97
And your answer will be three from local and three from online.
Oder of operations is this;
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
Answer:
50 deg
Step-by-step explanation:
The circles are congruent, so all radii of both circles are congruent.
The given central angles are congruent, so the triangles are congruent by SAS.
Since each triangle has 2 congruent sides (the radii), opposite angles are congruent.
m<DFE = m<J = 80 deg
m<H = m<G = x
m<H + m<G + m<J = 180
x + x + 80 = 180
2x + 80 = 180
2x = 100
x = 50
m<H = 50
1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
