The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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False Sometimes its different for all
The given function is,

The graph can be drawn as,
The period will be distance between two consequetive maximas,

Thus, period is correct.
The amplitude can be determined as,

Thus, amplitue is incorrect.
The range is,

Thus, the range is correct.
The midline is,

Thus, the midline is correct.
Thus, option (b) is the solution.
Answer:
0.368
Step-by-step explanation:
Number of red marbles= 3
Number of blue marbles= 4
Number of green marbles= 7
Total number of marbles= 3+4+7= 14
Let the first ball is taken out to be red
P(R)=
than again a second ball is drawn, number of balls left= 14-1=13
Number of red= 2
P(R)=
Total probability=
+
Total probability= 0.368
Hence, the correct answer is 0.368
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