3 years ago

42,429 rounded to the nearest ten thousand

Mathematics

1 answer:

pickupchik [31]3 years ago

4 0

It should be 40'000 I think......

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Darina [25.2K]

Answer:

54 is th area

Step-by-step explanation:

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7 0

3 years ago

Solve for the width in the formula for the area of a triangle

zmey [24]

Answer: $\frac{2A}{h} = w$

Step-by-step explanation:

The formula for area of a triangle is $A = wh\frac{1}{2}$

Now we have to isolate for w.

First multiply by the 2 which is the reciprocal of 1/2 to cancel it out.

$2A = wh\\$

Now divide by h to isolate w.

$\frac{2A}{h} = w$

4 0

3 years ago

Which two integers does the value of √88 lie?

Marizza181 [45]

88=4*22=> sqrt88=2sqrt22
sqrt22 is approximately sqrt25=5
so 4 < sqrt22 < 5
8 < 2sqrt22 < 10
8 < sqrt88 < 10

6 0

3 years ago

If k is non zero digit for which base of k is the sum, 1+kk=100 true?

Anna007 [38]

No, i don't think it's true

4 0

3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$