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mariarad [96]
3 years ago
12

A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5 m/s2. What is the mass of the bowling ball? Ik the answer

is 4.0, but I got it wrong for 4.00. I based the significant numbers off the 22.0 but apparently it's the 5.5. I always get it wrong when the question involves two numbers with different amounts of significant numbers (sometimes I use the smaller one but it wanted the bigger). How do I know when to use more or less significant numbers?
Mathematics
1 answer:
KiRa [710]3 years ago
5 0

Step-by-step explanation:

You should always use the least number of significant figures.  The exception is exact numbers or constants.

For example, there are 60 minutes in an hour.  Even though this number has one significant figure, it is an exact number.  So 15 minutes converted to hours would be 0.25 hr.

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How to subtract unlike fractions
topjm [15]
Find the common denominator for both unlike fractions.

EX:   1                        2
         12                      8

The lowest common factor is both fractions is 24.           Multiply both denominators to get 24. 

Do not forget to multiply the numerators with the number you used to multiply the denominators together.        

You do not have to multiply each side by the same number.
 
5 0
3 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
What is the measure of ∠XYZ? show your work
mezya [45]

Answer:

i don't know..........,......

7 0
2 years ago
A line with a slope of 4 passes through the point (2, 1). What is the equation of this line?
olasank [31]

Answer:

point slope form: y - 1 = 4 (x -2)

slope intercept form: y = 4x -7

Step-by-step explanation:

If you want it in point slope form it would be: y - 1 = 4 (x -2)

but if you want it in slope intercept form, you solve this equation

y -1 = 4 (x-2)

y-1 = 4x -8

 +1          +1

y = 4x -7 in slope intercept form

7 0
2 years ago
What is the domain of -2
Free_Kalibri [48]
The answer is 7x so I this helps you please thank me plz bye
5 0
2 years ago
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