1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irakobra [83]
3 years ago
15

how far would a 4.0 cm tall object be located from a reflecting surface with a focal lenght that is equal to 5 cm if it is to cr

eate an image seen 15 cm behind the mirror. Determine the image size​
Mathematics
1 answer:
katrin [286]3 years ago
5 0

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

Use the mirror equation:

1/di + 1/do = 1/f

where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)

Substitute and solve for do.

1/do + 1/(-10 cm) = 1/(15 cm)

1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)

do = 6 cm

Hope it helps you

Regards,

Rachana

You might be interested in
You want to purchase a pair of shoes for at least $150. You have $55 so far. You earn $10.00 per hour at your job write an inequ
VikaD [51]
55+10.00x ≥ 150 x ≥ 9.5 hours I hope that helps
7 0
3 years ago
The value of
marusya05 [52]

\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

\sf :\implies x = 1 + \sqrt{2}

So, the value of the fraction is 1 + √2.

4 0
2 years ago
HELP PLEASE:
sattari [20]

Answer:

Its 40 for the first and 20for the other one

Step-by-step explanation:

I just took the test.

3 0
3 years ago
Read 2 more answers
Solve for w, simplify your answer as much as possible
Akimi4 [234]

Answer:

W=3

Step-by-step explanation:

(6w + 4w)/48=5/8(taking lcm)

6w+4w=5/8*48

10w=30

W=3

Thanks for putting qsn, makes me remember this againa

6 0
3 years ago
One interior angle of a regular octagon is
Oksanka [162]

Answer:

<h2>135 degrees</h2>

<h2>To find the measure of the angles, we know that the sum of all the angles is 1080 degrees (from above)... And there are eight angles... So, the measure of the interior angle of a regular octagon is 135 degrees.</h2>

4 0
3 years ago
Read 2 more answers
Other questions:
  • While going on a field trip, a busload od 54 students will have to be split up into three groups. Two thirds will go into lunch
    13·1 answer
  • Where do I drag the last two
    15·1 answer
  • How to solve question 8 d? Thanks so much. Whenever answers gets brainliest, also they used the discriminant formula.
    13·1 answer
  • Is x^2-8x+64 a perfect square trinomial
    8·1 answer
  • Which is true about the diagram below?
    13·2 answers
  • What is the perimeter of the rectangle? L2FwcGhvc3RpbmdfcHJvZC9ibG9icy9BRW5CMlVwWmJyVDFqTFkzLXZ2RUFuT1lPWVJPbWl0N0JKUVhrVnZZbnVO
    11·1 answer
  • 1.what is definition and
    13·1 answer
  • Can Somone help me please :))
    15·1 answer
  • If f(x) = ax + c and f(3) = f(8), then a =
    15·1 answer
  • Please help ASAP! 20 points!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!