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Black_prince [1.1K]
3 years ago
9

Rick has 7 cats. Carrie has 14 cats. How many fewer cats does Rick have

Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

He has 7 fewer cats because

Step-by-step explanation:

14-7=7

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What is the probability of rolling 2 standard dice which sum to 11 ?
Fantom [35]

Answer:

1236

Step-by-step explanation:

5 0
3 years ago
PLZZZ HELP will mark brainliest!
erica [24]

Answer:

(3,8): No,  (-1,-11): Yes,  (2,7): Yes,  (0,-6): No

Step-by-step explanation:

Basically, you just substitute x and y with the numbers given.

18x - 3y = 15

y = 6x - 5

(3,8):

18(3) - 3(8) = 15

54 - 24 = 30  It is not equal to 15, so it does not work.

y = 6x - 5

8 = 6(3) - 5

8 = 13  It is not equal to 8, so it does not work.

Therefore, (3,8) is not a solution.

Try this for every pair and you will find that (-1,-11) and (2,7) are solutions.

I hope this helps!

8 0
2 years ago
Which equation represents a line that passes through (–9, –3) and has a slope of –6?
larisa [96]

Answer:

y = - 6x - 57

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 6, thus

y = - 6x + c ← is the partial equation

To find c substitute (- 9, - 3) into the partial equation

- 3 = 54 + c ⇒ c = - 3 - 54 = - 57

y = - 6x - 57 ← equation of line

4 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
The 2 points are reflections of each other across the x-or y-axis identify the axis help me please
sasho [114]
7. Y axis
8. X axis
9. X axis
10. Y axis
7 0
3 years ago
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