All categories

3 years ago

What is the common difference between the elements of the arithmetic sequence below?

Mathematics

2 answers:

galina1969 [7]3 years ago

7 0

Answer:

-4.5

Step-by-step explanation:

daser333 [38]3 years ago

5 0

-4.5 might be the answer im not very sure but yeah

You might be interested in

Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o

Ivahew [28]

Answer:

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

Step-by-step explanation:

Optimizing With Lagrange Multipliers

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

$\displaystyle C_i=3x_i+\frac{i}{40}x_i^2$

It means the cost for each generator is expanded as

$\displaystyle C_1=3x_1+\frac{1}{40}x_1^2$

$\displaystyle C_2=3x_2+\frac{2}{40}x_2^2$

$\displaystyle C_3=3x_3+\frac{3}{40}x_3^2$

The total cost of production is

$\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2$

Simplifying and rearranging, we have the objective function to minimize:

$\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)$

The restriction can be modeled as a function g(x)=0:

$g: x_1+x_2+x_3=1000$

$g(x_1,x_2,x_3)= x_1+x_2+x_3-1000$

We now construct the auxiliary function

$f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)$

$\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)$

We find all the partial derivatives of f and equate them to 0

$\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0$

$\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0$

$\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0$

$f_\lambda=x_1+x_2+x_3-1000=0$

Solving for \lambda in the three first equations, we have

$\displaystyle \lambda=3+\frac{2}{40}x_1$

$\displaystyle \lambda=3+\frac{4}{40}x_2$

$\displaystyle \lambda=3+\frac{6}{40}x_3$

Equating them, we find:

$x_1=3x_3$

$\displaystyle x_2=\frac{3}{2}x_3$

Replacing into the restriction (or the fourth derivative)

$x_1+x_2+x_3-1000=0$

$\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0$

$\displaystyle \frac{11}{2}x_3=1000$

$x_3=181.8\ MW$

And also

$x_1=545.5\ MW$

$x_2=272.7\ MW$

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

5 0

4 years ago

(5a+2)(a+4)= this is supposed to be a polynomial in standard form

Shkiper50 [21]

Answer:

5a²+22a+8

Step-by-step explanation:

(5a×a)+(5a×4)+(2×a)+(2×4)

=5a²+20a+2a+8

=5a²+22a+8

7 0

3 years ago

Help me please: 3/4 - 7/9 + 2/3 =

mojhsa [17]

Answer:

3/4-7/9+2/3=0.63

Step-by-step explanation:

.........

8 0

3 years ago

Read 2 more answers

How long did it take the 9000 N car to reach 100 km/hr?

Veronika [31]

100 seconds. The numbers on the left are seconds.

7 0

3 years ago

Write a recursive formula for a n a n , the n th n th term of the sequence 6 , − 12 , 24 , . . .

Anton [14]

Answer:

See below ↓↓

Step-by-step explanation:

a₁ refers to the first term of the sequence.

That is clearly : a₁ = 6

The formula for the nth term is :

aₙ = a₁rⁿ⁻¹
Common ratio (r) = quotient of consecutive terms
r = -12/6 = -2

Therefore, the nth term is :

aₙ = 6(-2)ⁿ⁻¹

4 0

2 years ago